Sum of three fractions

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\(\frac{1}{9}+\frac{1}{7}+\frac{1}{4}=?\)
\(\frac{157}{252}\)
\(\frac{147}{252}\)
\(\frac{137}{252}\)
\(\frac{127}{252}\)
\(\frac{117}{252}\)

Calculator
Hint \(\frac{1}{9}+\frac{1}{7}+\frac{1}{4}\)
\(=\frac{1\times{28}}{9\times{28}}+\frac{1\times{36}}{7\times{36}}+\frac{1\times{63}}{4\times{63}}\)
\(=\frac{28}{252}+\frac{36}{252}+\frac{63}{252}\)
\(=\frac{28+36+63}{252}\)
\(=\frac{127}{252}\)
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