Sum of three fractions
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Hint
\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{1\times{6}}{2\times{6}}+\frac{1\times{4}}{3\times{4}}+\frac{1\times{3}}{4\times{3}}\)
\(=\frac{6}{12}+\frac{4}{12}+\frac{3}{12}\)
\(=\frac{6+4+3}{12}\)
\(=\frac{13}{12}\)
\(=\frac{12+1}{12}\)
\(=1+\frac{1}{12}\)
\(=1\frac{1}{12}\)
\(=\frac{1\times{6}}{2\times{6}}+\frac{1\times{4}}{3\times{4}}+\frac{1\times{3}}{4\times{3}}\)
\(=\frac{6}{12}+\frac{4}{12}+\frac{3}{12}\)
\(=\frac{6+4+3}{12}\)
\(=\frac{13}{12}\)
\(=\frac{12+1}{12}\)
\(=1+\frac{1}{12}\)
\(=1\frac{1}{12}\)
