Sum of three fractions — Mathematics Practice Basic
Sum of three fractions: Mathematics Practice Basic-এর বহুনির্বাচনি প্রশ্ন ও উত্তর অনুশীলন।
মোট 15টি প্রশ্ন। এই অনুশীলনে 15টি প্রশ্ন রয়েছে।
- \(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}=?\)
- \(1\frac{1}{12}\)
- \(1\frac{5}{12}\)
- \(1\frac{7}{12}\)
- \(1\frac{1}{6}\)
- \(1\frac{5}{6}\)
- \(\frac{1}{5}+\frac{1}{4}+\frac{1}{6}=?\)
- \(\frac{47}{60}\)
- \(\frac{37}{60}\)
- \(\frac{57}{60}\)
- \(\frac{27}{60}\)
- \(\frac{17}{60}\)
- \(\frac{1}{7}+\frac{1}{5}+\frac{1}{8}=?\)
- \(\frac{121}{280}\)
- \(\frac{111}{280}\)
- \(\frac{131}{280}\)
- \(\frac{141}{280}\)
- \(\frac{151}{280}\)
- \(\frac{1}{9}+\frac{1}{7}+\frac{1}{4}=?\)
- \(\frac{157}{252}\)
- \(\frac{147}{252}\)
- \(\frac{137}{252}\)
- \(\frac{127}{252}\)
- \(\frac{117}{252}\)
- \(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}=?\)
- \(\frac{7}{12}\)
- \(\frac{5}{12}\)
- \(\frac{3}{12}\)
- \(\frac{1}{12}\)
- \(\frac{11}{12}\)
- \(\frac{1}{3}+\frac{1}{5}+\frac{1}{7}=?\)
- \(\frac{71}{105}\)
- \(\frac{61}{105}\)
- \(\frac{51}{105}\)
- \(\frac{41}{105}\)
- \(\frac{31}{105}\)
- \(\frac{1}{4}+\frac{1}{6}+\frac{1}{8}=?\)
- \(\frac{23}{24}\)
- \(\frac{13}{24}\)
- \(\frac{11}{24}\)
- \(\frac{15}{24}\)
- \(\frac{17}{24}\)
- \(\frac{1}{5}+\frac{1}{7}+\frac{1}{9}=?\)
- \(\frac{133}{315}\)
- \(\frac{153}{315}\)
- \(\frac{143}{315}\)
- \(\frac{163}{315}\)
- \(\frac{173}{315}\)
- \(\frac{1}{6}+\frac{1}{8}+\frac{1}{9}=?\)
- \(\frac{59}{72}\)
- \(\frac{49}{72}\)
- \(\frac{13}{24}\)
- \(\frac{29}{72}\)
- \(\frac{19}{72}\)
- \(\frac{1}{8}+\frac{1}{2}+\frac{1}{5}=?\)
- \(\frac{9}{40}\)
- \(\frac{7}{40}\)
- \(\frac{13}{40}\)
- \(\frac{23}{40}\)
- \(\frac{33}{40}\)
- \(\frac{1}{7}+\frac{1}{3}+\frac{1}{8}=?\)
- \(\frac{101}{168}\)
- \(\frac{103}{168}\)
- \(\frac{107}{168}\)
- \(\frac{109}{168}\)
- \(\frac{111}{168}\)
- \(\frac{1}{9}+\frac{1}{5}+\frac{1}{6}=?\)
- \(\frac{73}{90}\)
- \(\frac{43}{90}\)
- \(\frac{83}{90}\)
- \(\frac{53}{90}\)
- \(\frac{23}{90}\)
- \(2\frac{1}{2}+3\frac{1}{3}+4\frac{1}{4}=?\)
- \(10\frac{5}{12}\)
- \(10\frac{7}{12}\)
- \(10\frac{1}{12}\)
- \(10\frac{11}{12}\)
- \(10\frac{1}{6}\)
- \(3\frac{1}{5}+2\frac{1}{7}+3\frac{1}{8}=?\)
- \(8\frac{171}{280}\)
- \(8\frac{141}{280}\)
- \(8\frac{151}{280}\)
- \(8\frac{131}{280}\)
- \(8\frac{161}{280}\)
- \(2\frac{1}{9}+3\frac{1}{7}+5\frac{1}{4}=?\)
- \(10\frac{117}{252}\)
- \(10\frac{137}{252}\)
- \(10\frac{147}{252}\)
- \(10\frac{157}{252}\)
- \(10\frac{127}{252}\)