Sum of three fractions

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\(3\frac{1}{5}+2\frac{1}{7}+3\frac{1}{8}=?\)
\(8\frac{171}{280}\)
\(8\frac{141}{280}\)
\(8\frac{151}{280}\)
\(8\frac{131}{280}\)
\(8\frac{161}{280}\)

Calculator
Hint \(3\frac{1}{5}+2\frac{1}{7}+3\frac{1}{8}\)
\(=3+\frac{1}{5}+2+\frac{1}{7}+3+\frac{1}{8}\)
\(=8+\frac{1}{5}\frac{1}{7}\frac{1}{8}\)
\(=8+\frac{1\times{56}}{5\times{56}}+\frac{1\times{40}}{7\times{40}}+\frac{1\times{35}}{8\times{35}}\)
\(=8+\frac{56}{280}+\frac{40}{280}+\frac{35}{280}\)
\(=8+\frac{56+40+35}{280}\)
\(=8+\frac{131}{280}\)
\(=8\frac{131}{280}\)
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